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Home/ Questions/Q 8179353
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:58:58+00:00 2026-06-06T23:58:58+00:00

the simple code below // g++ centro.cc -o centro #include <iostream> using namespace std;

  • 0

the simple code below

// g++ centro.cc -o centro

#include <iostream>
using namespace std;

int  main(int argc, char *argv[])
{
    try
    {
        cout << "Going to throw" << endl;
        throw;
    }
    catch(...)
    {
        cout << "An exception occurred" << endl;
    }
    return 0;
}

produces an abort:

Going to throw
terminate called without an active exception
Aborted (core dumped)

I don’t understand what’s wrong, can anybody point me in the right direction?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:59:01+00:00Added an answer on June 6, 2026 at 11:59 pm

    Your line

    throw;
    

    is the syntax for re-throwing an exception in a catch block.

    You should write:

    throw std::exception();
    
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