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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T10:39:54+00:00 2026-06-09T10:39:54+00:00

There I though I understood Java generics until I tried to write the following:

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There I though I understood Java generics until I tried to write the following:

class A{}

class B{
    A a;

    <T extends A> T getA(){ 
       return a; // does not compile
    }
}

I get a compilation error saying the types are incompatible: required T, found A.

  1. Why am I getting the error?
  2. I would be happy to get a reference to an article that describes this kind of java generics pitfalls.

Thank you!

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  1. Editorial Team
    Editorial Team
    2026-06-09T10:39:55+00:00Added an answer on June 9, 2026 at 10:39 am

    If it compiled, it wouldn’t be type-safe:

    B b = new B();
    b.a = new A();
    
    SubclassOfA foo = b.<SubclassOfA>getA();
    

    The compiler can’t guarantee that a will be an instance of T, and it can’t even check it at execution-time due to type erasure – so it won’t compile.

    In general the Java Generics FAQ covers just about everything.

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