Question

this is a code example from lazyfoo’s SDL tutorials.

SDL_Surface *load_image( std::string filename ) { 

//Temporary storage for the image that's loaded 
SDL_Surface* loadedImage = NULL; 
//The optimized image that will be used 
SDL_Surface* optimizedImage = NULL; 

//Load the image 
loadedImage = SDL_LoadBMP( filename.c_str() ); 


//If nothing went wrong in loading the image 
if( loadedImage != NULL ) { 
    //Create an optimized image 
    optimizedImage = SDL_DisplayFormat( loadedImage ); 
    //Free the old image 
    SDL_FreeSurface( loadedImage ); 
} 

//Return the optimized image 
return optimizedImage; 
} 

Here shouldn’t optimizedImage go out of scope when it returns? seeing as it is local.

Answer 1

It does, but not the allocated memory pointed by it. It is a merely 4 byte pointer variable, the only thing needed from it is to retain its value.

The value is the address. The address is something allocated in manually controlled fashion, and deallocating it requires calling functions the compiler does not know about.