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Home/ Questions/Q 8320667
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:44:04+00:00 2026-06-08T22:44:04+00:00

This is a multipurpose question: How does this compare to the glibc strlen implementation?

  • 0

This is a multipurpose question:

  • How does this compare to the glibc strlen implementation?
  • Is there a better way to to this in general and for autovectorization.
#include <stdint.h>
#include <stdlib.h>
#include <string.h>
#include <limits.h>
#include <stdbool.h>
#include <stdlib.h>

/* Todo: Document */
#define WORD_ONES_LOW   ((size_t)-1 / UCHAR_MAX)
#define WORD_ONES_HIGH  (((size_t)-1 / UCHAR_MAX) << (CHAR_BIT - 1))

/*@doc
 * @desc: see if an arch word has a zero
 * #param: w - string aligned to word size
 */
static inline bool word_has_zero(const size_t *w)
{
    return ((*w - WORD_ONES_LOW) & ~*w & WORD_ONES_HIGH);
}

/*@doc
 * @desc: see POSIX strlen()
 * @param: s - string
 */
size_t strlen(const char *s)
{
    const char *z = s;

    /* Align to word size */
    for (; ((uintptr_t)s & (sizeof(size_t) - 1)) && *s != '\0'; s++);

    if (*s != '\0') {
        const size_t *w;

        for (w = (const size_t *)s; !word_has_zero(w); w++);
        for (s = (const char *)w; *s != '\0'; s++);
    }

    return (s - z);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:44:06+00:00Added an answer on June 8, 2026 at 10:44 pm

    Well, this implementation is based on virtually the same trick (Determine if a word has a zero byte) as the glibc implementation you linked. They do pretty much the same thing, except that in glibc version some loops are unrolled and bit masks are spelled out explicitly. The ONES and HIGHS from the code you posted is exactly himagic = 0x80808080L and lomagic = 0x01010101L form glibc version.

    The only difference I see is that glibs version uses a slightly different criterion for detecting a zero byte

    if ((longword - lomagic) & himagic)
    

    without doing ... & ~longword (compare to HASZERO(x) macro in your example, which does the same thing with x, but also includes ~(x) member). Apparently glibc authors believed this shorter formula is more efficient. Yet it can result in false positives. So they check for false positives under that if.

    It is indeed an interesting question, what is more efficient: a single-stage precise test (your code) or a two-stage test that begins with rough imprecise check followed, if necessary, by a precise second check (glibc code).

    If you want to see how they compare in terms of actual performance – time them on your platform and your data. There’s no other way.

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