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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:05:47+00:00 2026-05-23T09:05:47+00:00

This is in python language. I need to print this pattern, depending on the

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This is in python language.
I need to print this pattern, depending on the number of lines a user enters:

‘##’
‘# #’

The next pattern is three spaces away and so on…

This is my code but it prints the second number sign on a different line. I need them to go on the same line.

 def drawPatternIII (lines):
   for i in range(lines):
      for j in range(1):
          print('#')
      for j in range(i+1):
          print (' ', end = '')
      print ('#')

please help!

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  1. Editorial Team
    Editorial Team
    2026-05-23T09:05:47+00:00Added an answer on May 23, 2026 at 9:05 am

    You would need to add end="" to the first print() call. While you are at it, remove the pointless for loop with a single iteration.

    A concise alternative would be

    for i in range(lines):
        print("#" + " "*i + "#")
    
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