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Home/ Questions/Q 8355621
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T09:55:17+00:00 2026-06-09T09:55:17+00:00

This is my code: typedef struct{ char name[64]; } Cat; Cat createCat(char name[64]) {

  • 0

This is my code:

typedef struct{
  char name[64];
} Cat;

Cat createCat(char name[64]) {
  Cat newCat;

  newCat.name = name;

  return newCat;
}

It compiles with the following error message:

incompatible types when assigning to type ‘char[64]’ from type ‘char
*’

What am I doing wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T09:55:19+00:00Added an answer on June 9, 2026 at 9:55 am

    Array decay to pointers when passed to functions. So:

    Cat createCat(char name[64]) {
    

    is the same as:

    Cat createCat(char* name) {
    

    and the line:

    newCat.name = name;
    

    is attempting to assign a char* to a char[], as the error states. As Mystical has already commented, you need to use memcpy() or strcpy() (or strncpy()) to copy name to newCat.name. If you use memcpy() you must remember to null terminate newCat.name.

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