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Home/ Questions/Q 8258715
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T02:38:24+00:00 2026-06-08T02:38:24+00:00

This is my login.php <form action=index.php method=get> <?php error_reporting(E_ALL & ~E_NOTICE); ?> <?php session_start();

  • 0

This is my login.php

 <form action="index.php" method=get>


      <?php
     error_reporting(E_ALL & ~E_NOTICE);
      ?>


    <?php
    session_start(); 
    if( $_SESSION["logging"]&& $_SESSION["logged"])
    {

    printme(); }



    else {
    if(!$_SESSION["logging"])
    {  
    $_SESSION["logging"]=true;

    loginform();
    }
    else if($_SESSION["logging"])
     {
     $number_of_rows=checkpass();
     if($number_of_rows==1)
   {    
    $_SESSION[user]=$_GET[userlogin];

    $_SESSION[logged]=true;

    echo "<h1>You have logged in successfully</h1><br/>";
    echo "<a  href='logout.php'>Logout</a> | <a href='users.php'>Click to proceed</a>"; 

                             }
                                else {



                            loginform();
                            }
                        }
                     }








    function loginform()
    {

    print ("<center><div id='login_header'><b><font face='Arial Black' color='black' size='4px'>Sign in to Minquep!</font></b></div></cen                   ter>");
    print("<br/><br/>");
    print ("<center><label>Username:</label><input type='text' name='userlogin' size='20'><br/><label>Password:</label><input type='                password' name='password' size='20'></center>");
    print "<br/><input type='submit' value='Submit' name='submit' class='submit'>"; 


    }


    function checkpass()
    {

    $dbHost = 'localhost';
    $dbUser = 'root';
    $dbPass = '';
    $dbname = 'minquep_test';

    $conn = mysql_connect($dbHost,$dbUser,$dbPass); // Connection Code
    mysql_select_db($dbname,$conn); // Connects to database



    $sql = "select * from users where login='$_GET[userlogin]' and   password='$_GET[password]'";
    $result = mysql_query($sql,$conn) or die(mysql_error());
    $fetched = mysql_fetch_array($result);

    if ($fetched['user_type'] == "moderator"){
    echo '<script type="text/javascript">window.alert("You have logged in successfully!\n")</script>';
    echo "Welcome {$_SESSION['user']}";
    echo "<meta http-equiv=\"refresh\" content=\"0;URL=pages/moderator.php\">";
                    }
    if ($fetched['user_type'] == "agent"){
    echo '<script type="text/javascript">window.alert("You have logged in successfully!\n")</script>';
     echo "<meta http-equiv=\"refresh\" content=\"0;URL=pages/agent.php\">";


                    }



                    }



        function content(){
        print("<b><h1>hi mr.$_SESSION[user]</h1>");
        print "<br><h2>only a logged in user can see this</h2>";



        }

       function printme(){
        echo '<script type="text/javascript">window.alert("You have logged in successfully!\n")</script>';
        }

        ?>




                </form>

Now whenever a user logs in… if his user_type is “moderator” he will be redirected to moderator.php

and if his user_type is “agent” he will be redirected to agent.php

what i want to happen is to output the username and usertype in the pages that a user will be redirected to.

This is what I’ve got in my agent.php and moderator.php

<?php session_start();

    echo "Welcome {$_SESSION['user']} . And You are Logged in as /*USER TYPE SHOULD BE DISPLAYED HERE */ ";

 ?>

I get this error:

Screenshot of error

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T02:38:26+00:00Added an answer on June 8, 2026 at 2:38 am

    try this in your agent.php

    <?php session_start();
    
        if (array_key_exists('user', $_SESSION) && !empty($_SESSION['user'])) {
    
            echo "Welcome {$_SESSION['user']} . And You are Logged in as /*USER TYPE SHOULD BE DISPLAYED HERE */ ";
    
        } else {
    
            echo "Welcome stranger";
        }
    
     ?>
    
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