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Home/ Questions/Q 8280793
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T09:48:31+00:00 2026-06-08T09:48:31+00:00

This is my sample code: #include <iostream> using namespace std; class Base { public:

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This is my sample code:

#include <iostream>
using namespace std;

class Base
{
public:
    Base (int v, char z) {x=v;y=z;};
    int x;
    char y;
};

class Bar
{
public:
    Bar(int m, char n):q(m),s(n),base(q,s){};
    Base base;
    int q;
    char s;    
};

int main()
{
    Bar barObj(5,'h');    
    cout << barObj.base.x << barObj.base.y << endl;       
    return 0;
}

Why am I getting an output of 0?
http://ideone.com/pf47j

Also, in general, what is the right method to create a member object in another class and call the constructor of that object, as was done above with object base of class Base, inside class Bar?

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  1. Editorial Team
    Editorial Team
    2026-06-08T09:48:33+00:00Added an answer on June 8, 2026 at 9:48 am

    The initialization order of data members follow their declaration order, not the order you list their initializer. Thus, Bar::base is always initialized before Bar::q and Bar::s.
    As shown in http://ideone.com/M6iKR , for Bar::Bar(int m, char n), initialize base using m and n works fine.

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