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Home/ Questions/Q 8295947
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T14:47:30+00:00 2026-06-08T14:47:30+00:00

This is my sample file: <?xml version=1.0 encoding=UTF-8 ?> <testjar> <testable> <trigger>Trigger1</trigger> <message->2012-06-14T00:03.54</message> <sales-info>

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This is my sample file:

<?xml version="1.0" encoding="UTF-8" ?>
 <testjar>
 <testable>
  <trigger>Trigger1</trigger>
  <message->2012-06-14T00:03.54</message>
 <sales-info>
  <san-a>no</san-a>
  <san-b>no</san-b>
  <san-c>no</san-c>
  </sales-info>
  </testable>
  </testjar>

I need to extract xml tags from this-

e.g. output of above file should be

testjar
testable
trigger
message
sales-info
....
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T14:47:31+00:00Added an answer on June 8, 2026 at 2:47 pm
    $> cat ./text
    <?xml version="1.0" encoding="UTF-8" ?>
     <testjar>
     <testable>
      <trigger>Trigger1</trigger>
      <message>2012-06-14T00:03.54</message>
     <sales-info>
      <san-a>no</san-a>
      <san-b>no</san-b>
      <san-c>no</san-c>
      </sales-info>
      </testable>
      </testjar>
    

    And

    $> grep -P -o "(?<=\<)[^>?/]*(?=\>)" ./text
    testjar
    testable
    trigger
    message
    sales-info
    san-a
    san-b
    san-c 
    

    Regular expression (?<=\<)[^>?/]*(?=\>) consist of 3 parts:

    • (?<=\<): (?<=) is lookbehind operator, so it means “after <“;

    • [^>?/]*: not >,?,/ 0 or more times;

    • (?=\>): (?=) is lookahead operator, so it means “before >”

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