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Home/ Questions/Q 8334747
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:27:08+00:00 2026-06-09T03:27:08+00:00

This is my SQL: SELECT users.username, users.id_user, friends.name, friends.meet_date FROM users INNER JOIN friends

  • 0

This is my SQL:

"SELECT users.username, users.id_user, friends.name, friends.meet_date 
 FROM users INNER JOIN friends ON (users.id_user = friends.id_user) 
 GROUP BY username ORDER BY username";

This is the output on my webpage:

Username    Friend's Name    Meeting Date
George      Nicolas          2010
Man         Anatol           2008

For now, it selects just the first rows from database for each user.

Each table has an auto_increment, id_user for the first table and id_friend for the second one.

I would like it to show that friend which were meet last by each user.

I’ve tried to add an order by "meet_date DESC" but it doesn’t work.

How could I achieve my wish?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:27:10+00:00Added an answer on June 9, 2026 at 3:27 am

    The easy way is a subquery:

     SELECT 
       users.username, 
       users.id_user, 
       ( select friends.name  
         from friends 
         where (users.id_user = friends.id_user) 
         ORDER BY friends.meet_date desc
         LIMIT 1 ) as friend_name,       
       ( select friends.meet_date
         from friends 
         where (users.id_user = friends.id_user) 
         ORDER BY friends.meet_date desc
         LIMIT 1 ) as friend_meet_date
     FROM users 
     ;
    

    * Testing *

    create table users (username varchar(50), id_user int);
    create table friends ( name varchar(50), id_user int, meet_date int);
    
    insert into users values ( 'a', 1),('b',2);
    insert into friends values ('c', 1, 0), ('d',1,1);
    

    Results:

    | USERNAME | ID_USER | FRIEND_NAME | FRIEND_MEET_DATE |
    -------------------------------------------------------
    |        a |       1 |           d |                1 |
    |        b |       2 |      (null) |           (null) |
    

    Try it at sql fiddle.

    Notice thant a correlated subquery is not an elegant approach, is the easy approach.

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