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Home/ Questions/Q 1050165
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T16:43:47+00:00 2026-05-16T16:43:47+00:00

This is sample of my code. class SomeClass extends SomeOtherClass { function __construct($input) {

  • 0

This is sample of my code.

class SomeClass extends SomeOtherClass
{

    function __construct($input)
    {
        parent::__construct($input);
        $this->conn = new mysqli('a','b','c','d');
    }

    function getConnection()
    {
        return &$this->conn;
    }

}

My main object is that i want to return the MySQLi connection by referencing it instead of creating another MySQLi class.

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  1. Editorial Team
    Editorial Team
    2026-05-16T16:43:47+00:00Added an answer on May 16, 2026 at 4:43 pm

    It’s:

    function &getConnection()
    {
       return $this->conn;
    }
    

    and when calling:

    $conn = &$instance->getConnection();
    

    That’s how to return variables by reference in general, but for resource type variables you don’t need to.

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