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Home/ Questions/Q 539579
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:09:02+00:00 2026-05-13T10:09:02+00:00

this is the code: private TreeNode GetTopLevelNode(TreeNode childNode) { if (childNode == null) throw

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this is the code:

 private TreeNode GetTopLevelNode(TreeNode childNode)
    {
        if (childNode == null)
            throw new ArgumentNullException("childNode", "childNode is null.");

        if (childNode.Parent == null) return childNode;

        TreeNode node = childNode;
        while (true)
        {
            if (node.Parent == null)
            {
                return node;
            }
            node = node.Parent;
        }

    }

in the while loop, only if node.Parent == null, a node will be returned,

why the compiler doesn’t report “not all code paths return a value” error?

if the ‘node.Parent == null’ can’t be satisfied , then no tree node will be returned.
The compiler can’t detect this situation?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:09:03+00:00Added an answer on May 13, 2026 at 10:09 am

    Because you are using while(true){, there is no other way to exit the loop other than using the return. if node.parent == null cannot be satisfied, then it will be an infinite loop. Therefore, there is no way to get past the loop without returning, and the compiler doesn’t complain.

    Also, the code you specified would almost always return a null TreeNode, is that what you really wanted?

    Edit: I see you fixed that.

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