Question

Thought I understood how classes work, then I tried this code:

class user
  {
  var $dbcon;

  var $dbinfo;
  var $con;    
  var $error;

  function dbConnect()
    {

    $this->dbinfo['server'] = "localhost";
    $this->dbinfo['database'] = "foolish_faith";
    $this->dbinfo['user'] = "user";
    $this->dbinfo['password'] = "password";

    $this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database'];
    $this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']);
    $this->dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $this->error = $this->dbcon->errorInfo();

    if ($error[0] != "")
      {
      print "Error!";
      print_r($error);
      }
    }
  }

Now it just spits out this error:

Fatal error: Uncaught exception
‘PDOException’ with message ‘invalid
data source name’ in
E:\PortableApps\xampp\htdocs\dbcon.php:24
Stack trace: #0
E:\PortableApps\xampp\htdocs\dbcon.php(24):
PDO->__construct(”, NULL, NULL) #1
E:\PortableApps\xampp\htdocs\login.php(4):
user->dbConnect() #2 {main} thrown in
E:\PortableApps\xampp\htdocs\dbcon.php
on line 24

Can anybody see what I’m doing wrong, as I’m sure it has to do with my lack of knowledge when it comes to classes?

Answer 1

$this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database'];
$this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']);

When you acces variables of a class instance you have to use the -> operator. In this case you’d use $this->dbinfo instead of just $dbinfo and $this->con instead of $con. You’ve done it correctly on the left side, but missed some on the right.