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Home/ Questions/Q 8322747
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T23:29:20+00:00 2026-06-08T23:29:20+00:00

Today I saw this code, inside a class: static const uint32_t invalid_index = ~uint32_t();

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Today I saw this code, inside a class:

static const uint32_t invalid_index = ~uint32_t();

My question is, what is the return value of a uint32_t destructor, and why is it useful?

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  1. Editorial Team
    Editorial Team
    2026-06-08T23:29:21+00:00Added an answer on June 8, 2026 at 11:29 pm

    That’s not a destructor, but a bitwise NOT operator applied to a value-initialized uint32_t.

    A value initialized integral type is 0, so you’re taking the bitwise NOT of 0.

    Similar to:

    uint32_t x = uint32_t();  // 32 0's in binary form
    uint32_t y = ~x;          // 32 1's in binary form
    
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