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Home/ Questions/Q 3439314
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T08:17:41+00:00 2026-05-18T08:17:41+00:00

total newbie here. i was trying to replace a character in char * but

  • 0

total newbie here.
i was trying to replace a character in char * but my program gives error

#include <stdio.h>

int main(int argc, char **argv)
{
    char *mystring ="love is alweys better yoe";
    int count = 1;

    for (count ;  count < 23; count++)
    {     
    if ((mystring[count] == 0x65 )) //&& ((mystring[count+1] > 0x41) && (mystring[count+1] < 0x7A))) 
    {
      mystring[count] = 0x45; //here occur the freezing
      printf ("%c\n", mystring[count]); 
      //break;
    };
    };

    printf("%s\n",mystring);
    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-18T08:17:42+00:00Added an answer on May 18, 2026 at 8:17 am

    The

    char *mystring ="love is alweys better yoe"
    

    makes mystring read-only

    you need to copy the string into a buffer before you can change it

    e.g.

    char mystring[128];
    strcpy( mystring , "love is alweys better yoe" );
    
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