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Home/ Questions/Q 8309757
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T19:13:09+00:00 2026-06-08T19:13:09+00:00

using System.Linq; var a = new byte?[][,]{ new byte?[,]{{1}}, new byte?[,]{{1}}, new byte?[,]{{2}}, new

  • 0
using System.Linq;

var a = new byte?[][,]{
    new byte?[,]{{1}},
    new byte?[,]{{1}},
    new byte?[,]{{2}},
    new byte?[,]{{1, 2, 3}, {4, 5, 6}}};
a = a.Distinct().ToArray();

However ‘a’ still contains a duplicate. Am I doing this correctly?


Thanks. From the information in the answers.

class Nullable_Byte_2D_Array_EqualityComparer : IEqualityComparer<byte?[,]>
{
    public bool Equals(byte?[,] a, byte?[,] b)
    {
        var r = a.GetLength(0) == b.GetLength(0) &&
            a.GetLength(1) == b.GetLength(1);
        if (r)
        {
            var v = new byte?[a.Length];
            byte n = 0;
            foreach (byte? c in a)
            {
                v[n] = c;
                n++;
            }
            n = 0;
            foreach (byte? c in b)
            {
                if (c != v[n])
                    r = false;
                n++;
            }
        }
        return r;
    }
}

And

a = a.Distinct(new Nullable_Byte_2D_Array_EqualityComparer()).ToArray();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T19:13:11+00:00Added an answer on June 8, 2026 at 7:13 pm

    It doesn’t contain a duplicate. It contains two distinct arrays which happen to have the same values inside of them. Since arrays are reference types, Distinct() does a reference comparison by default; to change this behavior, use this override to specify your own comparer.

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