Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8230497
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T17:09:30+00:00 2026-06-07T17:09:30+00:00

val x = for(i <- 1 to 3) yield i x match { case

  • 0
val x = for(i <- 1 to 3) yield i
x match {
    case 1 :: rest => ... // compile error
}

constructor cannot be instantiated to expected type; found :
collection.immutable.::[B] required:
scala.collection.immutable.IndexedSeq[Int]

This is the same problem as MatchError when match receives an IndexedSeq but not a LinearSeq.

The question is, how to do it right? Adding .toList everywhere doesn’t seem right. And creating an own extractor which handles every Seq (as described in the answer of the other question) would lead to a mess if everybody would do it…

I guess the question is, why can’t I influence what the return type of sequence comprehensions is, or: why isn’t such a generalized Seq extractor part of the standard library?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-07T17:09:32+00:00Added an answer on June 7, 2026 at 5:09 pm

    Well, you can pattern-match any sequence:

    case Seq(a, b, rest @ _ *) =>
    

    For example:

    scala> def mtch(s: Seq[Int]) = s match { 
      |      case Seq(a, b, rest @ _ *) => println("Found " + a + " and " + b)
      |      case _ => println("Bah") 
      |    }
    mtch: (s: Seq[Int])Unit
    

    Then this will match any sequence with more than (or equal to) 2 elements

    scala> mtch(List(1, 2, 3, 4))
    Found 1 and 2
    
    scala> mtch(Seq(1, 2, 3))
    Found 1 and 2
    
    scala> mtch(Vector(1, 2))
    Found 1 and 2
    
    scala> mtch(Vector(1))
    Bah
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

implicit val odkaz = head; def vypis(implicit odkaz:Prvek):String = { odkaz match{ case null
When I evaluate a for in Scala, I get an immutable IndexedSeq (a collection
val cross = (for (x<-setA; y<-setB) yield (x,y)) val cross2 = (setA flatMap (x
how can I remove this yield's? I wanna use a map instead of: val
Can I yield into a Map? I've tried val rndTrans = for (s1 <-
Given, case class User(name: String, roles: List[String]) val users: List[User] = ... I'd like
I have a collection of ComboBox declared as below. val cmbAll = for (i
val implies = fn x y = case x of false andalso case y
val A = 3 val (A) = (3) Both correct. But: val (A,B) =
int val = 233; byte b = (byte) val; System.out.println(b); I have a simple

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.