Home/ Questions/Q 3396680
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-18T04:26:12+00:00

var add = []; add[0].url = data.url; add[0].photo = data.thumb; console.log(add); This’ll be an

  • 0
var add = [];

add[0].url = data.url;
add[0].photo = data.thumb;

console.log(add);

This’ll be an instant know for most JS people. The code above is failing, anyone able to tell me where I’m going wrong

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    add[0] doesn’t exist… .push something first.

    add.push({ url:data.url, photo:data.thumb })

    or

    add[0] = {};
add[0].url = 'blah';
add[0].photo = 'foo'
    • 0