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Home/ Questions/Q 8210533
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T10:06:05+00:00 2026-06-07T10:06:05+00:00

var data = [{offset: 2000, str:’foo’}, {offset: 4000, str:’bar’}]; for (var i=0; i<data.length; i++)

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var data = [{offset: 2000, str:'foo'}, {offset: 4000, str:'bar'}];

for (var i=0; i<data.length; i++) {
    var x = data[i];
    setTimeout(function(){printStuff(x.str)}, x.offset);
}

function printStuff(str) {
    console.log(str);
}

I was expecting to get printStuff('foo') at 2000 ms offset and printStuff('bar') at 4000 ms offset but instead it prints ‘bar’ both times. I’ve no idea what’s going on, help please.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T10:06:08+00:00Added an answer on June 7, 2026 at 10:06 am

    Do this :

    for (var i = 0; i < data.length; i++) {
        (function (x) {
            setTimeout(function () {
                printStuff(x.str)
            }, x.offset);
        })(data[i]);
    }
    

    Your problem is that x has changed in the closure when the function is called.

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