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Home/ Questions/Q 228589
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:41:41+00:00 2026-05-11T19:41:41+00:00

We recently upgraded the code to gcc4.3.3 from gcc4.2.4 . void testAndSet( volatile int*

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We recently upgraded the code to gcc4.3.3 from gcc4.2.4.

void testAndSet(  volatile int*  s, int* val )
{
   __asm__ __volatile__ ( "btsl   $0, %0\n   "
           "jc   bitSet\n   "
           "movl   $0, %1\n   "
           "jmp   returnVector\n"
           "bitSet:\n   "
           "movl   $1, %1\n"
           "returnVector: " : "=m"(*s), "=m"(*val) );
}

Our code now fails with the following errors,

lock.cxx: Assembler messages:
lock.cxx:59: Error: symbol `bitSet' is already defined
lock.cxx:61: Error: symbol `returnVector' is already defined
lock.cxx:59: Error: symbol `bitSet' is already defined
lock.cxx:61: Error: symbol `returnVector' is already defined

Those symbols weren’t found anywhere else. (Renaming them causes the same error with the new name).

What’s up with this? why do I get the errors twice?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:41:41+00:00Added an answer on May 11, 2026 at 7:41 pm

    Probably the optimizer has changed and is now inlining your testAndSet() function into 2 places. Because you are using global names for your labels, this does not work. You should use local names instead. E.g:

       __asm__ __volatile__ ( "btsl   $0, %0\n   "
               "jc   0f\n   "
               "movl   $0, %1\n   "
               "jmp   1f\n"
               "0:\n   "
               "movl   $1, %1\n"
               "1: " : "=m"(*s), "=m"(*val) );
    

    Local labels are just numbers; to disambiguate cases where there are many labels called “0” you need to use “jmp 0f” for forward jumps and “jmp 0b” for backward jumps.

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