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Home/ Questions/Q 8193059
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T04:20:57+00:00 2026-06-07T04:20:57+00:00

what am i doing wrong with my if statement that it doesn’t recognise if

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what am i doing wrong with my if statement that it doesn’t recognise if an element in a is equal to 0? what i am attempting to print is for ever 0 the program prints . and for ever 1 #. cheers.

a=[0,0,1,0,1,1,0,1,1,0,0,0,0,1]
print(a)
for i in range(len(a)):
    if a[i]==[0]:
        print('.', end='')
    else:
        print('#', end='')
print()

bash:

[0, 0, 1, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1]
##############
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  1. Editorial Team
    Editorial Team
    2026-06-07T04:20:59+00:00Added an answer on June 7, 2026 at 4:20 am

    You probably want

    if a[i] == 0:
    

    instead of

    if a[i] == [0]:
    

    You want to compare the items to the integer value 0, not to the single-element list [0].

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