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Home/ Questions/Q 8370501
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T13:55:37+00:00 2026-06-09T13:55:37+00:00

What is the best way in Python to check if a ZipFile object is

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What is the best way in Python to check if a ZipFile object is not already closed?

For the moment I am doing this in a class:

try:
    self.zf.open(archive_name).close()
except RuntimeError:
    self.zf = zipfile.ZipFile(self.path)

with self.zf.open(archive_name) as f: 
    # do stuff...

Is there a better way?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T13:55:38+00:00Added an answer on June 9, 2026 at 1:55 pm

    Internally, there is an open file pointer called fp that get’s cleared on close; you can test for that yourself too:

    if not self.zf.fp:
        self.zf = zipfile.ZipFile(self.path)
    

    See the zipfile module source; the open method raises the RuntimeError exception if not self.fp is True.

    Note that relying on such internal, undocumented implementations can be hairy; if future implementations change your code will break, perhaps in subtle ways. Make sure you have good test coverage for your project.

    Alternatively, you could create a ZipFile subclass and override the .close method to track the state, which would be less at risk of breaking due to internal changes:

    class MyZipFile(zipfile.ZipFile):
        closed = False
        def close(self):
            self.closed = True
            super(MyZipFile, self).close()
    

    and

    if self.zf.closed:
        self.zf = MyZipFile(self.path)
    

    with thanks to aknuds1 for the suggestion.

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