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Home/ Questions/Q 8180313
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T00:11:13+00:00 2026-06-07T00:11:13+00:00

What will be the answer to : class abcd { public static void main(String

  • 0

What will be the answer to :

class abcd
{
  public static void main(String ar[])
  {
    int a=2, b=3, c;
    c = a++ * --b - b++ + ++a;
    System.out.println(a+" "+b+" "+c);
  }
}

Compiler gave the output as : 4 3 6. I got a=4 and b=3, but i was unable to solve for c. I came out with c=7.

Too much confusion in operator precedence. Someone plz help. 🙁

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  1. Editorial Team
    Editorial Team
    2026-06-07T00:11:14+00:00Added an answer on June 7, 2026 at 12:11 am

    Operands are evaluated left to right, so your code is equivalent to:

    int a = 2, b = 3, c = 0;
    int tmp1 = a++; //tmp1 = 2, a = 3
    int tmp2 = --b; //tmp2 = 2, b = 2
    int tmp3 = b++; //tmp3 = 2, b = 3
    int tmp4 = ++a; //tmp4 = 4, a = 4
    c = tmp1 * tmp2 - tmp3 + tmp4; // c = 2 * 2 - 2 + 4 = 6
    

    As for the link you posted, it only says that the formula should be read as:

    c = ( ( (a++) * (--b) ) - (b++) + (++a) );
    
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