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Home/ Questions/Q 8285875
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T11:34:19+00:00 2026-06-08T11:34:19+00:00

When I alloc and init two NSString variables and compare their pointers, they are

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When I alloc and init two NSString variables and compare their pointers, they are the same. Here’s a snippet that shows this:

NSString *s1 = [[NSString alloc] initWithString:@"hello world"];
NSString *s2 = [[NSString alloc] initWithString:@"hello world"];

if (s1 == s2) {
    NSLog(@"==");
}else {
    NSLog(@"!=");
}

Why are s1 and s2 the same?

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  1. Editorial Team
    Editorial Team
    2026-06-08T11:34:20+00:00Added an answer on June 8, 2026 at 11:34 am

    There are three things going on here:

    Firstly, the two identical string literals you’re passing in to initWithString: will have the same address to start. This is an obvious optimization for constant data.

    Secondly, when you nest alloc and init with strings, the runtime performs an optimization, the alloc call essentially becomes a no-op. This is done using the NSPlaceholderString class. This means the pointer you get back here will be coming from initWithString:, not from alloc.

    Thirdly, under the hood, initWithString: is calling CFStringCreateCopy, which as you may find, has the following behavior: Since this routine is for creating immutable strings, it has an optimization. It simply calls CFRetain() and returns the same object that was passed in.

    Thanks for the very interesting question. I had fun figuring it out.

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