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Home/ Questions/Q 4273680
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T07:44:43+00:00 2026-05-21T07:44:43+00:00

When I have this code: $(img).each(function(i) { $(this).delay(i*100).fadeIn(‘slow’); }); Which can be seen live

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When I have this code:

$("img").each(function(i) {
   $(this).delay(i*100).fadeIn('slow');
});

Which can be seen live here to give a better example of what it does…

… How can I make those images appear in a random order? That means not from top left to bottom right, but randomly like image 45, image 100, image 3, etc … ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T07:44:44+00:00Added an answer on May 21, 2026 at 7:44 am

    http://blog.staydecent.ca/entry/jquery-random-each

    function randsort(c) {
        var o = new Array();
        for (var i = 0; i < c; i++) {
            var n = Math.floor(Math.random()*c);
            if( jQuery.inArray(n, o) > 0 ) --i;
            else o.push(n);
        }
        return o;
    }
    
    var e = $('div'); // The elements we're searching
    var c = e.size(); // Total number of those elements
    var r = randsort(c); // an array of the element indices in random order
    
    $("div").each(function(i) {
        var e = $(this);
        e.fadeTo(0, 0.05);
        setTimeout(function(){
            e.fadeTo(250, 1);
        }, r[i]*10);
    });
    
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