Question

When I print out the integers (1 or 0), all the iterations (there are 3 of them in this case) print out the correct number. First and the second one return 1, the last one returns zero. BUT, ‘if’ statement seems to display everything in it anyway. What am I doing wrong?

All the code below is inside a bigger ‘for’ loop.

$yn = 0;

if(!in_array($pos, $blocks)){
    $blocks[$x] = $pos;
    $x++;
    $yn = 1;
}
print_r($blocks);

print "YN: ".$yn; # this prints out 1, 1 and 0 on the last iteration

if(yn){
        # show some stuff (is displayed in all three iterations, but it shouldn't be on the last)
}

Answer 1

Try:

if($yn){

PHP is interpreting yn as a string, rather than as the variable you should be using.