Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 507749
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T06:50:11+00:00 2026-05-13T06:50:11+00:00

Why do I get the following exception when I did this, what mistake did

  • 0

Why do I get the following exception when I did this, what mistake did i made?
What is the right way to insert tuple into tables with AUTO_INCREMENT fields?
How about delete, is it possible to update the ids?

string connStr = "server=localhost;user=root;database=test;port=3306;password=XXX;";
MySqlConnection conn = new MySqlConnection(connStr);
try{
    MessageBox.Show("Hello");
    conn.Open();
    string s0 = "CREATE TABLE school.student ( id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, name VARCHAR(45) NOT NULL, PRIMARY KEY (id))";
    string s1 = "INSERT INTO school.student VALUES ( LAST_INSERT_ID(), \'john\' )";
    string s2 = "INSERT INTO school.student VALUES ( LAST_INSERT_ID(), \'mary\' )";
    MySqlCommand cmd = new MySqlCommand(s0, conn);
    cmd.ExecuteNonQuery();                        
    cmd = new MySqlCommand(s1, conn);
    cmd.ExecuteNonQuery();                        
    cmd = new MySqlCommand(s2, conn);
    cmd.ExecuteNonQuery();
    conn.Close();
}catch(Exception ex){
    TextWriter tw = new StreamWriter("C:\\test.txt");
    MessageBox.Show(ex.ToString());
    tw.WriteLine(ex.ToString());
}  

​

MySql.Data.MySqlClient.MySqlException: Duplicate entry '1' for key 'PRIMARY'
   at MySql.Data.MySqlClient.MySqlStream.ReadPacket()
   at MySql.Data.MySqlClient.NativeDriver.ReadResult()
   at MySql.Data.MySqlClient.ResultSet.NextResult()
   at MySql.Data.MySqlClient.MySqlDataReader.NextResult()
   at MySql.Data.MySqlClient.MySqlCommand.ExecuteReader(CommandBehavior behavior)
   at MySql.Data.MySqlClient.MySqlCommand.ExecuteNonQuery()
   at ProjectInfo.Connect.Exec(String commandName, vsCommandExecOption executeOption, Object& varIn, Object& varOut, Boolean& handled)
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T06:50:11+00:00Added an answer on May 13, 2026 at 6:50 am

    These lines are the problem:

    string s1 = "INSERT INTO school.student VALUES ( LAST_INSERT_ID(), \'john\' )";
    string s2 = "INSERT INTO school.student VALUES ( LAST_INSERT_ID(), \'mary\' )";
    

    See, the LAST_INSERT_ID() function returns the value of the last generated auto_increment value. At th time of your first insert, no insert has taken place yet and LAST_INSERT_ID() evaluates to NULL. Suppose your table was empty the row is inserted with the generated value of 1. At the time of the second insertt, LAST_INSERT_ID() will be 1 due to the previous row you inserted. So, this time, there is already a row with 1 in the db, and the second insert does not succeed because of the duplicate 1.

    Rewrite like this:

    string s1 = "INSERT INTO school.student (name) VALUES (\'john\' )";
    string s2 = "INSERT INTO school.student (name) VALUES (\'mary\' )";
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I seemed to get the following exception when trying to deploy my application: Caused
With my Ruby script: imap = Net::IMAP.new('imap.gmail.com') imap.login(some_email@host.com, password) I get the following exception:
Why do I get following error when trying to start a ruby on rails
When I process a cube in Visual Studio 2005 I get following message: Process
We get the following error; The request was aborted: Could not create SSL/TLS secure
I get the following error when running my Visual Studio 2008 ASP.NET project (start
I get the following error when building my Windows Forms solution: LC.exe exited with
I get the following error when trying to run the latest Cygwin version of
I get the following error when attempting to install RubyGems . I've tried Googling
I get the following error pretty regularly when compiling in Visual Studio and running

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.