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Home/ Questions/Q 8249535
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T23:34:43+00:00 2026-06-07T23:34:43+00:00

Why does #isValid(integer,1,5)# output YES? I expected it to output NO like #isValid(integer,1.5)# does.

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Why does #isValid("integer","1,5")# output YES? I expected it to output NO like #isValid("integer","1.5")# does.

I’m going to validate with <CFIF isvalid("integer","1,5") AND isnumeric("1,5")> …

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  1. Editorial Team
    Editorial Team
    2026-06-07T23:34:44+00:00Added an answer on June 7, 2026 at 11:34 pm

    Adobe is aware of this, but…

    State: Closed

    Status: Withdrawn

    Reason: AsDesigned

    https://bugbase.adobe.com/index.cfm?event=bug&id=3169196

    TBH I’m a little embarrassed to be using a language that can’t even validate integer correctly.

    UPDATE:

    Guess what, it’ll be addressed in CF12!

    There is no doubt that this behavior is incorrect. It is obviously
    wrong and it should be corrected. However, it has been like this
    forever and making such a fundamental change has a great potential to
    break a lot of applications. We dont want to do that in this release.
    As Rakshith has already communicated, we plan to take up such changes
    in ‘Dazzle’ where we will correct the behavior without worrying about
    backward compatibility.

    http://blog.adamcameron.me/2014/02/can-we-please-agree-that-adobe-is-not.html

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