Why does this code always produce x=2?
unsigned int x = 0;
x++ || x++ || x++ || x++ || ........;
printf("%d\n",x);
Why does this code always produce x=2 ? unsigned int x = 0; x++
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Why does this code always produce x=2?
unsigned int x = 0;
x++ || x++ || x++ || x++ || ........;
printf("%d\n",x);
the 1st
x++changes x to 1 and returns 0the 2nd
x++changes x to 2 and returns 1at which point the or short circuits, returns true, and leaves x at 2.