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Home/ Questions/Q 8178589
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Editorial Team
  • 0
Editorial Team
Asked: June 6, 20262026-06-06T23:48:16+00:00 2026-06-06T23:48:16+00:00

Why does this code attempt to hide the div but then show it again?

  • 0

Why does this code attempt to hide the div but then show it again? using firefox

$(document).ready(function(){

    $("#tool1").click(function(){
       if($('#status').height() > 100){
           $('#status').css('height','50px').show();
       }    
    });

});

Thanks for the help so far they all worked. However this is the exact code I have
DEMO

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:48:17+00:00Added an answer on June 6, 2026 at 11:48 pm
    $("#tool1").click(function(){
       if($('#status').height() > 100){
         $('#status').hide(500, function() {  // hide the div
            $(this)
                 .css('height','50px')  // change the height
                 .show(500); // then show again
         });
       }    
    });
    

    DEMO

    According to above comment

    $("#tool1").click(function(){
       var orig = $('#status').height(),
           target = orig == 250 ? 50 : 250;
           $('#status').animate({
               height: target      
           },1000);  
    });
    

    DEMO

    According to below comment

    • Button is inside #status

    Button inside demo

    According to your demo

    Change you code like:

    $(document).ready(function() {
        $("#tool1").click(function(e) {
            e.preventDefault(); // preventDefault() for pare reload
            var $statusDiv = $('#status');
            if ($statusDiv.height() > 100) {
                $statusDiv.height(50);
            }
            else {
                $statusDiv.height(250);
            }
        });
    });
    

    DEMO

    Note

    You can also remove href from #tool1

    Currently #tool1 is link tag, if you want to use a button, than just remove e.preventDefault() from above code.

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