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Home/ Questions/Q 8258939
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Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T02:43:11+00:00 2026-06-08T02:43:11+00:00

With this code: for (int i = 0; i <= (checkedListBoxPlatypi.Items.Count – 1); i++)

  • 0

With this code:

for (int i = 0; i <= (checkedListBoxPlatypi.Items.Count - 1); i++)
{
    if (checkedListBoxPlatypi.GetItemCheckState(i) == CheckState.Checked)
    {
        ReturnListPlatypi.Add(ParsePlatypusID(checkedListBoxPlatypi.GetItemText(i)));
    }
}

…and a CheckedListBox that does have text assigned to it via (FriendlyPlatypus is a string with content):

checkedListBoxPlatypi.Items.Add(FriendlyPlatypus);

…ParsePlatypusID() is being passed “0”…???

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T02:43:13+00:00Added an answer on June 8, 2026 at 2:43 am

    I’m assuming you didn’t add “i” to the listbox, so there wouldn’t be any text for that object. You just need the object directly:

    for (int i = 0; i <= (checkedListBoxPlatypi.Items.Count - 1); i++)
    {
        if (checkedListBoxPlatypi.GetItemCheckState(i) == CheckState.Checked)
        {
            ReturnListPlatypi.Add(ParsePlatypusID(checkedListBoxPlatypi.Items[i].ToString()));
        }
    }
    

    If, in fact, you had added an object through a databinding, and you wanted to get directly to the “DisplayMember” field, you would use:

    for (int i = 0; i <= (checkedListBoxPlatypi.Items.Count - 1); i++)
    {
        if (checkedListBoxPlatypi.GetItemCheckState(i) == CheckState.Checked)
        {
            ReturnListPlatypi.Add(ParsePlatypusID(checkedListBoxPlatypi.GetItemText( checkedListBoxPlatypi.Items[i])));
        }
    }
    
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