Question

1.Getting buildid from a buildlocation which is the last word after “\” which is “A1234ABCDE120083.1” in this case

2.After getting the buildid,am opening a file and then trying to match the line “Engr Label: Data_CRM_PL_177999” to get the label name which is “Data_CRM_PL_177999”

3.Final output should be “Data_CRM_PL_177999”

For some reason I am getting the following syntax error..

 import re

 Buildlocation= '\\umor\locations455\INT\A1234ABCDE120083.1'

 Labelgetbuildlabel(Buildlocation)

def getbuildlabel(BuildLocation):
buildid=BuildLocation.split('\')[-1]
Notes=os.path.join(BuildLocation,Buildid + '_notes.txt')
if os.path.exists(Notes):
    try:
        open(Notes)
    except IOError as er:
        pass
    else:
        for i in Notes.splitlines:
        if i.find(Engr Label)
            label=i.split(:)[-1]

print label//output should be Data_CRM_PL_177999

Output should be:-

Line looks like below in the file
Engr Label: Data_CRM_PL_177999

SYNTAX ERROR

 buildid=BuildLocation.split('\')[-1]
                                   ^
 SyntaxError: EOL while scanning string literal

Answer 1

In the line

buildid=BuildLocation.split('\')[-1]

The backslash is actually escaping the following quotation mark
So, Python thinks this is actually your string:

'[-1])

Instead, you should do the following:

buildid=BuildLocation.split('\\')[-1]

And Python will interpret your string to be

\\

Interestingly, StackOverflow’s syntax highlighter hints at this issue. If you look at your code, it treats everything after that first slash as part of the string, all the way to the end of your code sample.

You also have a few other issues in your code, so I tried cleaning it up a bit for you. (However, I don’t have a copy of the file, so obviously, I wasn’t able to test this)

import re
import os.path

build_location= r'\\umor\locations455\INT\A1234ABCDE120083.1'


label = get_build_label(build_location)

# Python prefers function and variable names to be all lowercase with
# underscore separating words.
def get_build_label(build_location):
    build_id = build_location.split('\\')[-1]
    notes_path = os.path.join(build_location, build_id + '_notes.txt')
    # notes_path is the filename (a string)
    try:
        with open(notes_path) as notes:
            # The 'with' keyword will automatically open and close
            # the file for you
            for line in notes:
                if line.find('Engr Label'):
                    label = line.split(':')[-1]
                    return label
    except IOError:
        # No need to do 'os.path.exists' since notes_path doesn't
        # exist, then the IOError exception will be raised.
        pass
print label