1.php
...
<script src="/jquery-1.3.1.min.js" type="text/javascript"></script>
<script type="text/javascript">
var a = $a
var b = $b
var c = $c
apclick = function() {
$.ajax({
url: 'a1.php',
data: { a: a, b: b, c: c },
datatype: json,
success: function(results) {
if (results.msg == 'success') {
alert(a)
alert(b)
alert(c)
} else {
alert(results.msg)
}
},
error: function(results) {
alert("Data returned: " + results.msg )
}
});
setTimeout("location.reload(true);", 3000)
return false;
}
</script>
.....
<strong><br><a href="#" onclick="apclick();return false;">Afiseaza </a></strong>
a1.php
<?php
$return = array();
$a = $_POST['a'];
$b = $_POST['b'];
$c = $_POST['c']
if ($a == "hello") {
$return['msg'] = 'success';
$return['a'] = "Buna";
};
if ($b == "say") {
$return['msg'] = 'success';
$return['a'] = "Spune";
};
if ($c == "man") {
$return['msg'] = 'success';
$return['a'] = "Om";
};
header("Content-type: application/json");
echo json_encode($a);
echo json_encode($b);
echo json_encode($c);
?>
Questions is:
How send a,b,c to a1.php and receive a,b,c in 1.php
The code provided had several syntax errors, you should have fixed them before posting it.
Anyway, here is the working code for you:
And the a1.php: