1) When statements such as
cout << 3.0 + 3 ;
are made, how does one know whether the value passed to cout is an int or a float?
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1) When statements such as
cout << 3.0 + 3 ;
are made, how does one know whether the value passed to cout is an int or a float?
It’s neither. It’s a double.
3.0has type double, and3is promoted to double for the addition; the result of adding a double to a double is a double. That’s independent of what’s being done with the result.There are a bunch of overloaded shift-left operators for ostreams, and there’s one for an argument of type double on the right-hand side, so that’s the one that’s called:
For what it’s worth, that’s a member function, not a free function.