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Home/ Questions/Q 6667207
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:54:31+00:00 2026-05-26T02:54:31+00:00

A bit of code: public interface IMyInterface { int GetIt(); } public class MyImplementation

  • 0

A bit of code:

public interface IMyInterface
{
    int GetIt();
}

public class MyImplementation : IMyInterface
{
    public int GetIt()
    {
        return 10;
    }
}

   [Test]
    public void Testit()
    {
        Method<MyImplementation>();
    }

    private void Method<T>()
        where T : class , IMyInterface
    {
        var mock = new Mock<T>();
        mock.Setup(m => m.GetIt()).Returns(() =>
                                               {
                                                   return 40;
                                               });

        Assert.AreEqual(40, mock.Object.GetIt());
    }

Notice that when newing up the Mock I’m using the generic T, however since T is constrained to being a reference type and of type IMyInterface, I can set up the methods no problem. For some reason though, it always fails, and calls the actual implementation of MyImplementation as opposed to the Mocked one.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:54:32+00:00Added an answer on May 26, 2026 at 2:54 am

    You are essentially mocking a class method and for that the method has to be virtual.

    Try

    public class MyImplementation : IMyInterface
    {
        public virtual int GetIt()
        {
            return 10;
        }
    }
    
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