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Home/ Questions/Q 6475237
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:40:50+00:00 2026-05-25T06:40:50+00:00

A block of code similar to this sparked some debate on to which part

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A block of code similar to this sparked some debate on to which part of the code was most efficient or if there was a more correct way to do this. One argument was that the cast was more efficient than creating a string to parse. One argument was that the multiple class casts was creating more objects than creating the string to parse.

What is the “best practice”?

Object some_num_obj;
double some_num;
if(some_num_obj instanceof Integer)
{
    some_num = (double) (int) (Integer) some_num_obj;
}
else if(some_num_obj instanceof Double)
{
    some_num = (Double) some_num_obj;
}
else
{
     some_num = Double.parseDouble(some_num_obj.toString());
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:40:51+00:00Added an answer on May 25, 2026 at 6:40 am

    The most efficient and possibly the fastest is to use Number.doubleValue and Double.parseDouble

    if(some_num_obj instanceof Number)
        some_num = ((Number) some_num_obj).doubleValue();
    else
        some_name = Double.parseDouble(some_num_obj.toString());
    
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