Question

"A definition for a static data member may be provided in a namespace scope
 enclosing the definition of the static member's class template."

It means …

Is this correct…..

namespace N{
template<typename T>class A{
public: 
   static int x;
   static int fun();
 };

}
namespace N1{
template<class T>int A<T>::x=10; }
namespace N2{template<class T>int A<T>::fun(){return 10;} }
int main(){  return 0; }

According to the statement…whether my program is correct…

Otherwise…ca any one expalain this statement…With a program….
IT is the point from ISO Standard c++.chapter 14.5.1.3, point 1

Answer 1

If you check the standard you should see the example.

A definition for a static data member may be provided in a namespace scope enclosing the definition of the static member’s class template. [Example:

template<class T> class X {
    static T s;
};
template<class T> T X<T>::s = 0;

—end example]

Your program is not correct because

template<class T> A<int>::x=10;
template<class T> A<int>::fun(){return 10;}

did not use the template parameter T (and do you mean Ex instead of A?). Since you’re specializing a template, you should write

template<> int Ex<int>::x = 10;
template<> int Ex<int>::fun() { return 10; }

within the namespace N. (Not inside other namespaces like N1 or N2. It must be defined in the same namespace where Ex is declared.)