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Home/ Questions/Q 963405
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:39:57+00:00 2026-05-16T01:39:57+00:00

A dict dic = { 1: ‘a’, 2: ‘a’, 3: ‘b’, 4: ‘a’, 5:

  • 0

A dict

dic = {
 1: 'a', 
 2: 'a', 
 3: 'b', 
 4: 'a', 
 5: 'c', 
 6: 'd', 
 7: 'd', 
 8: 'a', 
 9: 'a'}

I want to remove duplicate values just keep one K/V pair,
Regarding the “key” selection of those duplicated values, it may be max or min or by random select one of those duplicated item’s key.

I do not want to use a k/v swap since that can not control the key selection.

Take value “a” for example

 1: 'a', 
 2: 'a', 
 4: 'a', 
 8: 'a', 
 9: 'a'

the max key will be {9: ‘a’} and the min will be {1: ‘a’}, and the random will choise any one of it.

And, if the key is other kind of hashable value, for example, string, then how to do such a selection?

Can anyone share me an idea?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:39:58+00:00Added an answer on May 16, 2026 at 1:39 am
    import itertools as it
    
    newdic = {}
    for v, grp in it.groupby(sorted((v, k) for k, v in dic.items)):
      newdic[min(k for _, k in grp)] = v
    

    Or other “selection” functions in lieu of min (which, of course, does work fine even if keys are strings — will give you the “lexically first” key in that case).

    The one case in which the selection function needs some care is when the keys corresponding to the same value may be non-comparable (e.g., complex numbers, or, in Python 3, objects of different not-all-numeric types). Nothing a key= in the min won’t cure;-).

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