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Home/ Questions/Q 599623
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:31:06+00:00 2026-05-13T16:31:06+00:00

A direct cut and paste of the following algorithm: def msort[T](less: (T, T) =>

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A direct cut and paste of the following algorithm:

def msort[T](less: (T, T) => Boolean)
            (xs: List[T]): List[T] = {
  def merge(xs: List[T], ys: List[T]): List[T] =
    (xs, ys) match {
      case (Nil, _) => ys
      case (_, Nil) => xs
      case (x :: xs1, y :: ys1) =>
        if (less(x, y)) x :: merge(xs1, ys)
        else y :: merge(xs, ys1)
    }
  val n = xs.length / 2
  if (n == 0) xs
  else {
    val (ys, zs) = xs splitAt n
     merge(msort(less)(ys), msort(less)(zs))
  }
}

causes a StackOverflowError on 5000 long lists.

Is there any way to optimize this so that this doesn’t occur?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:31:06+00:00Added an answer on May 13, 2026 at 4:31 pm

    It is doing this because it isn’t tail-recursive. You can fix this by either using a non-strict collection, or by making it tail-recursive.

    The latter solution goes like this:

    def msort[T](less: (T, T) => Boolean) 
                (xs: List[T]): List[T] = { 
      def merge(xs: List[T], ys: List[T], acc: List[T]): List[T] = 
        (xs, ys) match { 
          case (Nil, _) => ys.reverse ::: acc 
          case (_, Nil) => xs.reverse ::: acc
          case (x :: xs1, y :: ys1) => 
            if (less(x, y)) merge(xs1, ys, x :: acc) 
            else merge(xs, ys1, y :: acc) 
        } 
      val n = xs.length / 2 
      if (n == 0) xs 
      else { 
        val (ys, zs) = xs splitAt n 
        merge(msort(less)(ys), msort(less)(zs), Nil).reverse
      } 
    } 
    

    Using non-strictness involves either passing parameters by-name, or using non-strict collections such as Stream. The following code uses Stream just to prevent stack overflow, and List elsewhere:

    def msort[T](less: (T, T) => Boolean) 
                (xs: List[T]): List[T] = { 
      def merge(left: List[T], right: List[T]): Stream[T] = (left, right) match {
        case (x :: xs, y :: ys) if less(x, y) => Stream.cons(x, merge(xs, right))
        case (x :: xs, y :: ys) => Stream.cons(y, merge(left, ys))
        case _ => if (left.isEmpty) right.toStream else left.toStream
      }
      val n = xs.length / 2 
      if (n == 0) xs 
      else { 
        val (ys, zs) = xs splitAt n 
        merge(msort(less)(ys), msort(less)(zs)).toList
      } 
    }
    
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