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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:23:01+00:00 2026-05-27T18:23:01+00:00

A function returns two lists which are logically mapped one-to-one . Suppose name =

  • 0

A function returns two lists which are logically mapped one-to-one. Suppose

name = ["facebook", "twitter", "myspace"]
hits = [4000, 2500, 1800]

Therefore, hits for facebook are 4000, twitter 2500, and myspace 2500.

I want to convert these two separate lists into a list of dictionaries like

[
  {name: 'facebook',data: [4000]},
  {name: 'twitter',data: [2500]},
  {name: 'myspace',data: [1800]}
]

My solution to do this is:

data = [
    {"name":l, "data":[v]}
    for idx1, l in enumerate(labels)
    for idx2, v in enumerate(values)
    if idx1 == idx2
    ]

Is there a more elegant way of dealing with logical one-to-one mapping or is my solution precise?

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:23:02+00:00Added an answer on May 27, 2026 at 6:23 pm

    You could do:

    [{"name": n, "data": [h]} for n, h in zip(name, hits)]
    

    While this does what you asked for, there’s probably more data structure here than you really need. Consider:

    >>> dict(zip(name, hits))
    {'twitter': 2500, 'myspace': 1800, 'facebook': 4000}
    

    This provides the same data set in an easier-to-access data structure.

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