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Asked: 2026-05-30T08:57:47+00:00

A = <<hello>>. B = <<A:80/binary, 100:8>>. It gives me: ** exception error: bad

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A = <<"hello">>.
B = <<A:80/binary, 100:8>>.

It gives me:

** exception error: bad argument

and <<"hello">>. works, but:

A = "hello".
<<A>>.

can not work.

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1 Answer

  1. Editorial Team

    A doesn’t have size 80 bytes which obviously doesn’t match A:80/binary in first case. 

    1> A = <<"hello">>.
<<"hello">>
2> B = <<A/binary, 100:8>>.
<<"hellod">>
3> Pad = 80 - size(A), C = <<A/binary, 0:Pad/unit:8, 100:8>>.
<<104,101,108,108,111,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
  0,0,0,0,0,0,...>>

    <<"hello">> is syntactic sugar for <<$h,$e,$l,$l,$o>>. Bit syntax expression assumes 8/integer,unsigned,big,unit:1 type specification by default. A is not integer so <<A>> raises badarg exception in second case.

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