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Home/ Questions/Q 8020605
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T21:44:07+00:00 2026-06-04T21:44:07+00:00

<a href=http://www.chrisstucchio.com/blog/2012/bandit_algorithms_vs_ab.html>Why Multi-armed Bandit algorithms are superior to A/B testing (with Math)</a>, <a href=user?id=yummyfajitas>yummyfajitas</a>,

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<a href="http://www.chrisstucchio.com/blog/2012/bandit_algorithms_vs_ab.html">Why Multi-armed Bandit algorithms are superior to A/B testing (with Math)</a>, <a href="user?id=yummyfajitas">yummyfajitas</a>, <a href="item?id=4060658">11 comments</a>, 

How to scrape through an html page that has the above written html as content and get data out like this:

link = http://www.chrisstucchio.com/blog/2012/bandit_algorithms_vs_ab.html
text = Why Multi-armed Bandit algorithms are superior to A/B testing (with Math)
user_id = yummyfajitas
item_id = 4060658
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T21:44:08+00:00Added an answer on June 4, 2026 at 9:44 pm

    If it’s in this exact same order every time:

    html = r'<a href="http://www.chrisstucchio.com/blog/2012/bandit_algorithms_vs_ab.html">Why Multi-armed Bandit algorithms are superior to A/B testing (with Math)</a>, <a href="user?id=yummyfajitas">yummyfajitas</a>, <a href="item?id=4060658">11 comments</a>, '
    
    from BeautifulSoup import BeautifulSoup
    
    soup = BeautifulSoup(html) #sort the html
    bowl = soup.findAll('a') #find all links in the html
    
    link = bowl[0]['href'] #find the first 'a' tags href
    text = bowl[0].contents[0] #find the first tags url
    user_id = bowl[1]['href'].split('?id=')[1] #split on '?id=' and take the second  value. could be [-1] too
    item_id = bowl[2]['href'].split('?id=')[1]
    
    print 'link:', link
    print 'text:', text
    print 'user_id:', user_id
    print 'item_id:', item_id
    
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