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Home/ Questions/Q 6211119
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:16:56+00:00 2026-05-24T06:16:56+00:00

A Lock is always followed by a try/finally block, why? ReentrantReadWriteLock readWriteLockBitmap = new

  • 0

A Lock is always followed by a try/finally block, why?

ReentrantReadWriteLock readWriteLockBitmap = new ReentrantReadWriteLock();
Lock read = readWriteLockBitmap.readLock();
Lock write = readWriteLockBitmap.writeLock();
int shared = 0;

public void function1(){
    read.lock();
    try{
        //reading shared int
    }
    finally{
        read.unlock();
    }
}

public void function 2(){
    write.lock();
    try{
        //modify shared int
    }
    finally{
        write.unlock();
    }
}

Why having this try/finally block and not simply writing the code as follows:

ReentrantReadWriteLock readWriteLockBitmap = new ReentrantReadWriteLock();
Lock read = readWriteLockBitmap.readLock();
Lock write = readWriteLockBitmap.writeLock();
int shared = 0;

public void function1(){
    read.lock();
    //reading shared int
    read.unlock();
}

public void function 2(){
    write.lock();
    //modify shared int
    write.unlock();
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T06:16:56+00:00Added an answer on May 24, 2026 at 6:16 am

    In case anything goes wrong (Exception being thrown etc.) you want to make sure the lock is released no matter what. It’s just standard practice, even though in this case may technically be unnecessary.

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