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A long double is known to use 80 bits.
2^80 = 1208925819614629174706176;
Why, when declaring a variable such as:
long double a = 1208925819614629174706175; // 2^80 - 1
I get a warning saying: Integer constant is too large for its type.
1208925819614629174706175is an integer literal, not a double. Your program would happily convert it, but it would have to be a valid integer first. Instead, use a long double literal:1208925819614629174706175.0L.