Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6238961
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T11:18:31+00:00 2026-05-24T11:18:31+00:00

A point from the ISO C++ draft (n3290): 3.4.2/3 Argument Dependant Name Lookup: Let

  • 0

A point from the ISO C++ draft (n3290):

3.4.2/3 Argument Dependant Name Lookup:

Let X be the lookup set produced by unqualified lookup (3.4.1) and
let Y be the lookup set produced by argument dependent lookup
(defined as follows). If X contains

  • a declaration of a class member (#1) or
  • a block-scope function
    declaration that is not a using-declaration (#2) or
  • a declaration
    that is neither a function or a function template (#3)

then Y is empty. Otherwise Y is the set of declarations found in
the namespaces associated with the argument types as described below.
The set of declarations found by the lookup of the name is the union
of X and Y.

Is there an example code snippet that demonstrates ADL involving #1, #2 and #3?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-24T11:18:31+00:00Added an answer on May 24, 2026 at 11:18 am

    I think this code covers all the cases (also available at http://ideone.com/CbyJv). If you don’t select C++0x in ideone, then case #2 is allowed (but gcc 4.5.2 catches it).

    #include <iostream>
    
    // ::f
    void f (int i) { std::cout << "::f\n" ; }
    
    // Simple case
    void OK1() {
      f (99) ; // Calls ::f
    }
    
    // Argument-dependend lookup
    namespace MyNamespace {
    struct S { int i ; } ;
    void f (S& s) { std::cout << "MyNamespace::f\n" ; }
    }
    
    void OK2() {
      MyNamespace::S s ;
      f (99) ;   // Calls ::f
      f (s) ;    // Calls MyNamespace::f because the type of s is declared in MyNamespace
    }
    
    // Declaration of a class member (#1)
    struct C {
      static void ERROR1() {
        MyNamespace::S s ;
        f (s) ;        // Error: MyNamespace::f not matched, because Y is empty (#1)
      }
      static void f() { // Declaration of a class member (#1)
        std::cout << "C::f\n" ;
      }
    } ;
    
    // Block-scope function declaration (#2)
    void ERROR2() {
      void f() ; // Block-scope function declaration (#2)
      MyNamespace::S s ;
      f (s) ;    // Error: MyNamespace::f not matched, because Y is empty (#2)
    }
    
    // Declaration that is neither a function or a function template (#3)
    void ERROR3() {
      MyNamespace::S s ;
      f (s) ;            // OK: MyNamespace::f called
      typedef int f[3] ; // Declaration that is neither a function or a function template (#3)
      f (s) ;            // Error: MyNamespace::f not matched, because Y is empty (#3). This is an initialiser
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

A point from ISO C++ DRAFT n3290 :Argument dependant Name Lookup : section 3.4.2,
A point from iso C++ n3290 :Argument dependant Name Lookup: section 3.4.2, para 4
A point from N3290 draft ISO Standard, §3.4.1/12: During the lookup of a name
A point from ISO draft N3290 : Unqualified Name Lookup :section 3.4.1, para 14:
A point from the ISO C++ Draft n3290 : 3.4.0 2nd point A name
A point from the ISO C++ draft (n3290): 3.4.3.2/1 Namespace members If the nested-name-specifier
A point from n3290 ISO draft: Lambda expressions : section 5.1.2, para 6: The
A point from ISO draft n3290 section 3.4.2 paragraph 1: When the postfix-expression in
A point from ISO draft n3290 section 3.3.9 paragraph 4: The declarative region of
A point from the ISO C++ draft (n3290): 3.4.3.2/1 Namespace members For a namespace

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.