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Asked: May 11, 20262026-05-11T13:40:10+00:00 2026-05-11T13:40:10+00:00

A problem that I often face with Hibernate is having a list (call it

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A problem that I often face with Hibernate is having a list (call it listA) of objects that I want to persist against an entity (myEntity) but having to first compare them to the existing list on the entity and delete those that aren’t in listA.

The simple way to do this is to clear the list on the Entity and just add all of listA to the entity, however I often have to perform some validation on the elements before they are deleted – eg. to check whether this user is allowed to delete them.

My current approach feels awkward:

//Delete the elements that have been removed //Use toArray to avoid ConcurrentModificationException for(ObjectA a : myEntity.getObjectAList().toArray(new ObjectA[myEntity.getObjectAList().size()])) {     if(!listA.contains(a)) {          //Check if this element can be deleted         if(canDelete(a)) {             entityManager.remove(a);             myEntity.getObjectAList().remove(a);         }     } }  //Add the elements that don't already exist for(ObjectA a : listA) {     if(!myEntity.getObjectAList().contains(a)) {         myEntity.getObjectAList().add(a);     } } 

Any room for improvement?

Thanks.

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  1. 2026-05-11T13:40:10+00:00Added an answer on May 11, 2026 at 1:40 pm

    Try using:

    myEntity.getObjectAList().removeAll(listA); 

    this will only keep the objects which aren’t already in listA.

    Also, if you need to do something like this manually in the future, use an iterator:

    Iterator<?> it = myEntitiy.getObjectAList().iterator(); while (it.hasNext()) {     ... } 

    Then it.next() will give you the next item in the array, and it.remove() will remove the last value of next() for you, without giving an exception if you keep looping.

    If you need to also have the ability to add a new value while looping, consider using listIterator() instead.

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