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Home/ Questions/Q 5843257
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T12:07:46+00:00 2026-05-22T12:07:46+00:00

a query : $query=mysql_query(SELECT content_id, COUNT(*) FROM votingapi_vote WHERE value_type = option AND value

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a query :

$query=mysql_query(SELECT content_id, COUNT(*) FROM votingapi_vote WHERE value_type = option  AND value = 1 GROUP BY content_id)

if i assign it to $result .

while ($obj = db_fetch_object ($result)) {
  $output .= $obj->content_id.'<br>' . $obj->count;
}

how to output the count number? after the $obj->content_id. there is no number printed. thank you.

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  1. Editorial Team
    Editorial Team
    2026-05-22T12:07:47+00:00Added an answer on May 22, 2026 at 12:07 pm

    You need an alias for your column COUNT(*) (i.e. rename the column) :

    SELECT content_id, COUNT(*) as count FROM [...]
    

    Then use the variable :

    $obj->count
    
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