Question

A regular expression to return logging.jar. Path can contain varying levels of depthness.

I think I need to use the ‘.’ operator but am unsure how to handle varying amount of slashes ?

Both below test cases should return logging.jar

C:/proj/test/tester/base/logging.jar
C:/proj/test/tester/base/leveldeeper/logging.jar

Answer 1

.*/([^\\.]*)\\..*
in group 1 you’ll get the name of the file.extension doesn’t matter.
If you want to get name only for jar files use this pattern:
.*/([^\\.]*)\\.jar

.* is a greedy regex and it will match until the last /.After / there is only file’s name with extension and you just need to get it’s name. [^\\.]* is greedy too and will match until the last dot (.), in fact what you need because the last dot is the extension separator.