Question

A short summary of the question: I have a parent class which is extended by a child class.

     public class Parent{

        public Parent(){
          //constructor logic
        }
     }

This child class calls the Parent’s constructor using super:

     public class Child extends Parent{

         public Child(){
            super();
         }
     }

I was wondering if I were to extend the Child class if I could call the super() method in the Grandchild class’ constructor:

    public class Grandchild extends Child{

         public Grandchild(){
            super();
         }
    }

Answer 1

super() is calling constructor one level up on the inheritance and it is called implicitly, if there is a no-arg constructor.

Objects are initialized from the top level of inheritance, in your case it is Object > Parent > Child > Grandchild.

From the documentation:

If a constructor does not explicitly invoke a superclass constructor, the Java compiler
automatically inserts a call to the no-argument constructor of the superclass. If the super 
class does not have a no-argument constructor, you will get a compile-time error. Object does 
have such a constructor, so if Object is the only superclass, there is no problem.