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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:32:59+00:00 2026-05-28T03:32:59+00:00

A simple and seemingly reliable way to do locking under bash is: exec 9>>lockfile

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A simple and seemingly reliable way to do locking under bash is:

exec 9>>lockfile
flock 9

However, bash notoriously propagates such a fd lock to all forked stuff including executed programs etc.

Is there any way to tell bash not to duplicate the fd? It’s great that the lock is attached to a fd which gets removed when the program terminates, no matter how it gets terminated.

I know I can do stuff like:

run_some_prog 9>&-

But that is quite tedious.

Is there any better solution?

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:33:00+00:00Added an answer on May 28, 2026 at 3:33 am

    You can use the -o command line option to flock(1) (long option --close, which might be better for writing in scripts for the self-documenting nature) to specify that the file descriptor should be closed before executing commands via flock(1):

       -o, --close
              Close the file descriptor on which the lock is held
              before executing command.  This is useful if command
              spawns a child process which should not be holding
              the lock.
    
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